# Evaluate the polynomial at the given values of x

**evaluate the polynomial**function for the

**given value of x**. 6. f (

**x**) = 5x3 + 3x2 –

**x**+ 7;

**x**= 2. STEP 1 Write the coefficients of f (

**x**) in order of descending exponents. Write the

**value**at which f (

**x**) is being evaluated to the left. STEP 2.

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**evaluate**a

**polynomial**for a

**given value**of a variable was direct substitution. Simply put, that means you plugged that

**value**into the expression and found the result. EXAMPLE: If P(

**x**) = 2x2 + 3x – 10, find P when

**x**=. Free

**polynomial**equation calculator - Solve

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**polynomial**p (

**x**) with integer coeffcients, then I can easily

**evaluate**this at some integer to get an exact answer. That is, I can write something like. sage: p=1+x+2*x^2+x^3+x^4 sage: p(2) 35. But If I instead want to

**evaluate**this

**polynomial**

**at**a root of unity (I take w to be a primitive 5 :th root of unity in the.

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**polynomial**variables. The above

**polynomial**is said to be of the n th degree, i.e. deg (f (

**x**)) = n where n represents the highest variable exponent. Horner's rule for

**polynomial**division is an algorithm used to simplify the process of evaluating a

**polynomial**f (

**x**)

**at**a certain

**value**

**x**= x0 by dividing the

**polynomial**. What is y=the square root of

**x**graphed as, factoring

**polynomials**solver, sample General Aptitude test question with answer. +state board of 10 standard maths previous question paper, best book for learning beginning algebra, get equation matlab spline, to the power of a fraction 3/4.

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**The**naive solution for evaluating a

**polynomial**

**of**degree n at q points takes O ( n q) time, by using Horner's rule q times. It turns out there are faster algorithms to do this, namely, in O ( max ( n, q) log 2 max ( n, q)) time. For simplicity of exposition, let me assume q = n, so the goal is to

**evaluate**

**the**

**polynomial**f (

**x**)

**at**points

**x**1.